I need to help my 6th grader with her math. Does anyone know the solution for ax+b=c when a is negative?

Hi Kat,





I assume that x is the unknown that you are trying to solve for. If a is negative, then the equation reads as





-a·x + b = c





So, we find the solution by first subtracting b from both sides of the equation:





-a·x = c - b (subtract b from both sides of the equation)





Next, divide both sides by -a to get





x = (c - b) / (-a)





James ☺☺☺☺☺

I need to help my 6th grader with her math. Does anyone know the solution for ax+b=c when a is negative?
U chose a completely wrong solution.


all solutions here are right , except that of james %26amp; x97free


james add "-" to a but this is wrong as a is already a -ve number


example if a=-5 so he made it -a= -(-5)=5 Report It

Reply:ax+b=c


ax=c-b


x=(c-b)/a


it makes no difference if a is -ve or +ve
Reply:Well when a is negative:


a(x) + b= -c as long as |a(x)| %26gt; b


a(x) + b = c as long as |a(x)| %26lt; b





if you are looking to solve for x then:





1) subtract b from both sides


ax+b=c


ax = c - b





2) Solve for x by dividing both sides by a





ax = c - b


x = (c - b) / a
Reply:solution: x = a/(c+b) ...You switch the fraction around because a would be the denominator and it is negative. if a was positive it would be x = (c+b)/a
Reply:if a is negative and 0%26lt;b%26lt;c:


x = (c-b)/a so x is a negative number.





If a is negative and 0%26lt;c%26lt;b:


x is a positive number.





if a is positive and 0%26lt;b%26lt;c:


x is positive.





if x is positive and 0%26lt;c%26lt;b:


x is negative.
Reply:The answer is the same whether a is negative or positive.


x=(c-b)/a
Reply:uhm, thats not specific enough. ax + b = c can be so much in math. ex) graphing, equations, inequalites, etc.





i can try to help as much i can...





when a is negative....?





-5x + 10 = 35


- 10 - 10


-5x = 25


-5 -5


x = -5





???? does that help?





if yes, your welcome, if nnot, sorry and repost.