I.C.S.E. - fundamental maths of 8th Std about profit & Loss?

A Person bought an article and sold it at a loss of 10% . If he had bought it for 20% less and sold it for Rs.55 more , He would have had a profit of 40% . find C.P. of article ?

I.C.S.E. - fundamental maths of 8th Std about profit %26amp; Loss?
let the C.P. be rs.x


so he sold it for rs 0.90x


if he had bought it for rs 0.80x and sold it for rs 0.90X+55 the profit is 40%


i.e.(0.90x+55-0.80x)/0.80x =40/100


0.10x+55=0.32x


0.22x=55


x=55/0.22=rs.250
Reply:I don't understand your question exactly, but here goes...





The equation I got was (.9x + 55) - (.8x) = 1.4*(.8x)


(Sale price) - (Purchase Price) = (40% profit on current purchase price)


Then x is about 33.95