how do you do this Pythagorean theorem math problem
b=12, c=13
Pythagorean theorem math problem?
You add and subtract based on which variable you are solving for. If your variable is 'a' then you need to subtract both sides by 'b' in order to get 'a' by itself. Or, if you are solving for 'c' you just plug in 'a' and 'b'.
You basically need to get the variable you are solving for by itself, and to do that you need to subtract or add what is there.
Hope that helps!
Reply:a = 5
Since a^2 + 12^2 = 13^2, we know a^2 = 169 - 144 = 25 and therefore a = 5.
Of course, even though you use b and c in the givens, you could want "d." In that case, 12^2 + 13^2 = d^2 so: d^2 = 144 + 169 = 313 and d = 313^½.
But I will go with the idea that you want a = 5 since that is one of the basic Pythagorean Triples.
Added:
In all of them, you use the a^2 + b^2 = c^2 relationship. Because you are likely, as in this one, sometimes given c and one of a and b, you sometimes have to subtract. That is because you want to get all the numbers in the equation to one side, leaving the variable by itself (and then take the square root). In the ones that give you a and b, you add because the c is already by itself. That is why you sometimes subtract, sometimes add.
Reply:13^2-12^2=a^2
or 169-144=a^2
25=a^2
5=a
Reply:The Pythagorean Theorem:
a^2+b^2=c^2
a^2+12^2=13^2
a^2+144=169
a^2+144-144=169-144
a^2=25
a=5
Reply:a^+b^=c^
so.....
a^+12^=13^
a^+144=169
-144
a^=25
sq both sides
a=sqrt 25
a=5
Reply:a^2 + b^2 = c^2
a^2 = 13^2 - 12^2
= 169 - 144
= 25
so a = 5
Reply:square the thirteen and the twelve and subtract the answers from each other. Then you take the square ROOT of what you get.
Reply:a^2 + b^2 = c^2
plug in b and c
so you get a^2 + 12^2 = 13^2
subtract 144 on both sides
so it would be 169 - 144 = a^2
and then just square root
Reply:a^2 + b^2 = c^2
plug in and solve for a
Reply:a=5
use the formula: C^2=A^2+B^2
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