Another math ?.. Show that for an isosceles right triangle c=a(square root)of 2?

In an isosceles right triangle, sides a and b are equal and c is the hypotenuse. Pythagorean's Theorum says that a^2 plus b^2 = c^2 for all right triangles. here, a and b are equal, so you can say 2(a^2)=c^2. If you want to solve for c, you find that c = a(rad2)