Could anyone please help me with these math problems..??
1. Using the Pythagorean Theorem, find the length of hypotenuse C given that side A = 4 and side B = 6.
A) side C = 24
B) side C = 52
C) side C = 7.21
D) side C = 4.47
2. Using the Pythagorean Theorem, find the length of side B given that side A = 10 and hypotenuse C = 26.
A) Side B = 16
B) Side B = 27.85
C) Side B = 8.48
D) Side B = 24
3. Choose the best description of the inequality x %26lt; 2 graphed on a number line.
A) A closed dot on 2, with an arrow pointing to the right
B) A closed dot on 2, with an arrow pointing to the left
C) An open dot on 2, with an arrow pointing to the right
D) An open dot on 2, with an arrow pointing to the left
4. Which of the following inequalities is equivalent to:
-5 %26lt; x + 1
A) x %26lt; -4
B) x %26gt; -4
C) x %26lt; -6
D) x %26gt; -6
5. x / 3 + 5x / 3
A) 2x
B) x
C) 5x^2 / 9
D) 5x^2 / 3
Help with these math problems please?
The Pythagorean theorem: a^2 + b^2 = c^2, where c is the hypotenuse of a right triangle.
1. A=4 and B=6
4^2 + 6^2 = 16 + 36 = 52 = C^2
REMEMBER TO TAKE THE SQUARE ROOT!
this is C^2, so we need to take the square root to find C
C = sqrt (52) = 7.21,
so the answer is C.
2. A=10, C=26, so we need to solve for B
since A^2 + B^2 = C^2,
then B^2 = C^2 - A^2
B^2 = 26^2 - 10^2 = 676 + 100 + 776
remember ... take the square root ...
B = sqrt (776), which is about 27.85
so the answer is B.
3. x %26lt; 2, so the range of values does not include 2. Open dot or closed dot?
.
.
.
.
.
.
.
... right. Open dot.
Values are greater to the right, and less to the left.
x %26lt; 2. I'll let you draw the conclusion.
4. -5 %26lt; x +1. You would treat this the same as any equation and solve for x. Subtract 1 from both sides, and you're left with -5 - 1 %26lt; x +1 -1,
which is the same as -6 %26lt; x, or x %26gt; - 6.
5. x/3 + 5x/3.
The denominators are the same so it's the same as
(x + 5x)/3, which is 6x/3. Divide the top and bottom by 3, and you have your answer.
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