Here are two math problems that I'm stuck on could anyone please help??
1. Quadrilateral A B C D, segment A C forms two triagnles. Angle B is 82, angle B A C is 71, angle A C D is 92, and angle D is 51
The longest side of triangle ABC is
A)Segment AB
B)Segment BC
C)Segment AC
D)Segment AD
2. Quadrilateral A B C D, segment A C forms two triagnles. Angle B is 82, angle B A C is 71, angle A C D is 92, and angle D is 51
The shortest side of triangle ACD is
A)Segment AD
B)Segment CD
C)Segment AC
D)Segment AB
2 math problems , Could anyone please help ??
1. longest side of triangle ABC is segment AC.
The longest side of a triangle is opposite the greatest angle.
2. shortest side of triangle ACD segment DC
The shortest side if a triangle is opposite the smallest angle.
Reply:1. if bac is 71 then bca is 27 because 27+82+71=180 and that is how many degrees is in a triangle
and cad is 39 because angle b is 82- c is 119 d is 51 added gets 250 360-252 = 108 108-71= 37 so angle a is 108
longest side is ac because it is across from b ( the biggest angle) 82
2. angle b is 82
angle d is 51
bac is 71
180-71-82=27
angle bca is 27
acd is 92
180-92-51=37
cad is 37
the shortest side is dc because it is across from the smallest angle, cad, 37
aster
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