Maths: A man tosses 3coins A,B,C. if A shows a head the man scores 1point, if B shows a head he sores 2points?

and if C shows a head he scores 3point. Calculate the expectation of his score.

Maths: A man tosses 3coins A,B,C. if A shows a head the man scores 1point, if B shows a head he sores 2points?
A = 1 No of points on a head in A


B = 2 No of points on a head in B


C = 3 No of points on a head in C





P(A) = P(B) = P(C) = 1/2


Expected Score = P(A)A + P(B)B + P(C)C


= 1/2(1+2+3) = 3 points


Expected score = 3 points
Reply:Possible outcomes %26amp; scores are:


HHH - 6


HHT - 3


HTH - 4


THH - 5


HTT - 1


THT - 2


TTH - 3


TTT - 0





Each of these 8 outcomes is equally likely. The sum of the possible scores is 24, and so the average (which is also the expected value) is 3.
Reply:0.5*0.5*0.5 = 0.125 or 1/8
Reply:E(Score) = Sum {Score * P(Score) }





P(head with A) = .5 ---%26gt; Score is 1


P(head with B) = .5 ---%26gt; Score is 2


P(head with C) = .5 ---%26gt; Score is 3





E(Score) = (.5*1) + (.5*2) + (.5*3) = 3