Math help please?

can someone please help me with these math questions please?? thanks





Rectangle A B C D with side A B is labeled 3y + 10 and side C D is labeled 2y + 20 . ABCD is a rectangle. Find the length of AB


10


20


30


40








CDEF is a square. Solve for x if the measure of angle FCD = 2x + 45.





22.5


90


45


62.3











A B C D is drawn with diagonals B D and A C. ABCD is a rectangle. Diagonal BD = 25. Find the length of AC.


15


20


25


30





Rhombus G H I J is drawn with diagonals H J and G I intersection at point K. GHIJ is a rhombus. The measure of angle HKI = 4y + 10. Solve for y.





90


45


20


30








Rhombus G H I J is drawn with diagonals H J and G I intersection at point K. GHIJ is a rhombus.The measure of angle GHI = 66. Find the measure of angle GHK.


66


33


90


132

Math help please?
Okee dokee





1) If those are opposite sides of the rectangle, then 3y + 10 = 2y + 20, because opposite sides are equal. Thus, y = 10, and the side length is 40.





2) The interior angles of a square are all 90 degrees. Thus, 2x + 45 = 90 and x = 22.5





3) The diagonals on a rectangle are equal, so AC is also 25.





4) The angles created by the intersecting diagonals of a rhombus are 90 degree angles; therefore, 4y + 10 = 90, and y = 20.





5) GHK would be exactly half of GHI, so GHK = 33.
Reply:1. Because it's a rectangle, AB = CD, so





3y+10 = 2y+20


y+10 = 20


y = 10


AB = 3y+10 = 40





2. %26lt;FCD has to = 90, so





2x+45 = 90


2x = 45


x = 22.5





3. The diagonals inside a rectangle are equal.





AC = BD = 25.





4. A rhombus' sides are all the same length, so the angles formed in the center are all right angles.





90 = 4y+10


80 = 4y


20 = y





5. The diagonal bisects the original angle of the sides.





%26lt;GHI = 66, so %26lt;GHK = 33.