has to kinda look like a c++ code.
something like this:
#include%26lt;iostream%26gt;
#include%26lt;math.h%26gt;
#include%26lt;iomanip%26gt;
using namespace std;
int main()
{
int n=[2,4,6,8,10,29,11,12,13,14,15,16,18,19...
int o=[49,48,46,45,44,43,42,39,38,37,36,33,3...
d1=math.rand()*[n];
d2=math.rand()*[n];
d3=math.rand()*[o];
cout%26lt;%26lt;"1"%26lt;%26lt;"-"%26lt;%26lt;"2"%26lt;%26lt;"-"%26lt;%26lt;"3"%26lt;%26lt;endl;
cout%26lt;%26lt;d1%26lt;%26lt;"-"%26lt;%26lt;d2%26lt;%26lt;"-"%26lt;%26lt;d3%26lt;%26lt;endl;
return 0;
}
but i'm not sure it's right! :D
C++ problem. array n=[2,4,6,8,10,29,11,12]; array o=[49,48,46,45,44]. need 2 select a random number 4rm both?
//get # of elements
int sizeA = (sizeof n) / (sizeof n[0])
int sizeB = (sizeof o) / (sizeof o[0])
//A random integer in the valid range of array N
int random_integer = rand() % sizeA;
cout %26lt;%26lt; n[random_integer];
//A random integer in the valid range of array O
random_integer = rand() % sizeB;
cout %26lt;%26lt; o[random_integer];
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